Investigating Forces & Motion

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INI File | 1998-02-10 | 8.2 KB | 295 lines

[question1] type:3 caption:\ A car is travelling at a constant speed on a straight road. Which \ graph shows how its displacement changes with time? correct:2g16b wrong1:2g16a wrong2:2g16c wrong3:2g16d feedback:\ For constant-speed motion in a straight line, displacement increases \ by equal amounts in equal time intervals. This produces a straight \ line graph with a constant slope. [question2] type:1 image:2g17 caption:\ This graph shows how the velocity of a train increases as it pulls \ away from the station. What is the train's acceleration? correct:0.5 m/s2 wrong1:1.0 m/s2 wrong2:1.5 m/s2 wrong3:0.1 m/s2 feedback:\ You can calculate an object's acceleration by measuring the gradient \ of the line on its velocity time-graph. The train's velocity increases \ by 4.0 m/s in 8.0 s. Its acceleration is therefore equal to 4.0 ÷ \ 8.0 = 0.5 m/s2. [question3] type:1 image:2g18 caption:\ This graph shows the displacement against time for an object moving in \ a straight line. What is the best description of the object's \ motion? correct:constant negative velocity wrong1:constant positive velocity wrong2:positive acceleration wrong3:negative acceleration feedback:\ The graph shows that the object's displacement decreases by equal \ amounts in equal time intervals. It therefore has a constant negative \ velocity. [question4] type:3 caption:\ Which of the graphs below shows an object with a uniform negative \ acceleration? correct:2g20a wrong1:2g20b wrong2:2g20c wrong3:2g20d feedback:\ The velocity of an object with uniform negative acceleration decreases \ by equal amounts in equal time intervals. The object's velocity-time \ graph is therefore a straight line with a negative gradient. [question5] type:3 caption:\ Which of the graphs below shows an object moving with a constant \ velocity? correct:2g16b wrong1:2g16a wrong2:2g16c wrong3:2g16d feedback:\ The displacement of an object moving with a constant velocity \ increases by equal amounts in equal time intervals. The \ displacement-time graph is therefore a straight line with a positive \ gradient. [question6] type:1 image:2g22 caption:\ This graph shows how the displacement of a moving object changes with \ time. What is its velocity? correct:2.0 m/s wrong1:1.0 m/s wrong2:3.0 m/s wrong3:4.0 m/s feedback:\ The object's velocity is the gradient of its displacement-time graph. \ The object's displacement increases by 4.0 m in 2.0 s. Its velocity is \ therefore equal to 4.0 ÷ 2.0 = 2.0 m/s. [question7] type:1 image:2g23 caption:\ This graph shows how the velocity of a moving object changes with \ time. What is its acceleration? correct:4.0 m/s2 wrong1:3.0 m/s2 wrong2:2.0 m/s2 wrong3:1.0 m/s2 feedback:\ The object's acceleration is the gradient of its velocity-time graph. \ The object's velocity increases by 4.0 m/s in 1.0 s. Its acceleration \ is therefore equal to 4.0 ÷ 1.0 = 4.0 m/s2. [question8] type:2 caption:To what is the gradient of a velocity-time graph equal? correct:acceleration wrong1:displacement wrong2:speed wrong3:distance feedback:The gradient of a velocity-time graph is equal to acceleration. [question9] type:2 caption:To what is the gradient of a displacement-time graph equal? correct:velocity wrong1:displacement wrong2:acceleration wrong3:distance feedback:The gradient of a displacement-time graph is equal to velocity. [question10] type:2 caption:\ A car is travelling at a constant positive velocity. A graph of its \ displacement against time will be: correct:a straight line with a constant positive gradient wrong1:an upward curve wrong2:a horizontal line wrong3:a downward curve feedback:\ The displacement-time graph for a car travelling at a constant \ positive velocity is a straight line with a constant positive \ gradient. [question11] type:1 image:2g24 caption:\ This graph shows the velocity of a cyclist on a straight journey to \ the post box and back. At which point does the return journey \ start? correct:C wrong1:A wrong2:B wrong3:D feedback:\ The return journey starts when the cyclist's velocity first becomes \ negative and the journey back towards the starting point begins. This \ occurs at point C. [question12] type:1 image:2g25 caption:\ This graph shows the displacement of car from its starting point. At \ which point on the journey does the car's speed reach a maximum? correct:B wrong1:C wrong2:D wrong3:A feedback:\ The car's velocity can be calculated by measuring the gradient of its \ displacement-time graph. The maximum gradient (and thus the car's \ maximum velocity) is at point B on the graph. [question13] type:1 image:2g26 caption:\ This graph shows the displacement against time for two runners in a \ race. How far are they from the start when runner A overtakes runner \ B? correct:4 000 m wrong1:3 000 m wrong2:2 000 m wrong3:1 000 m feedback:\ When one runner overtakes the other, they are both at the same place \ at the same time. This is where the two lines on the graph cross. At \ this point, both runners are 4 000 m from the start. [question14] type:1 image:2g27 caption:\ This graph shows displacement against time for two cars in a race. How \ far are they from the finish when car B overtakes car A? correct:10 km wrong1:30 km wrong2:20 km wrong3:40 km feedback:\ When one car overtakes the other, they are both at the same place at \ the same time. This is where the two lines on the graph cross. At this \ point, both cars are 10 km from the finish. [question15] type:1 image:2g28 caption:\ Which line on this displacement-time graph shows an object moving with \ a velocity of 2.0 m/s? correct:C wrong1:A wrong2:B wrong3:D feedback:\ Velocity can be calculated by measuring the gradient of a \ displacement-time graph. The displacement of object C increases by 4.0 \ m in 2.0 s. Its velocity is therefore equal to 4.0 ÷ 2.0 = 2.0 \ m/s. [question16] type:1 image:2g29 caption:\ Which line on this velocity-time graph shows an object accelerating at \ 5.0 m/s2? correct:D wrong1:C wrong2:A wrong3:B feedback:\ Acceleration can be calculated by measuring the gradient of a \ velocity-time graph. The velocity of object D increases by 10 m/s in \ 2.0 s. Its acceleration is therefore equal to 10 ÷ 2.0 = 5.0 \ m/s2. [question17] type:1 image:2g30 caption:\ This graph shows displacement against time for a ball thrown \ vertically into the air and then caught again. For how many seconds is \ the ball in the air? correct:3.0 s wrong1:2.0 s wrong2:4.0 s wrong3:5.0 s feedback:\ The ball's displacement returns to 0.0 after 3.0 s, when it is caught \ again. [question18] type:1 image:2g30 caption:\ This graph shows displacement against time for a ball thrown \ vertically into the air and then caught again. What is the maximum \ height reached by the ball? correct:10 m wrong1:3.0 m wrong2:1.5 m wrong3:11 m feedback:\ The maximum height reached by the ball is its maximum displacement. \ This is 10 m. [question19] type:1 image:2g31 caption:\ This graph shows the speed of a falling raindrop against time. What is \ the raindrop's terminal velocity? correct:4.0 m/s wrong1:2.0 m/s wrong2:5.0 m/s wrong3:3.0 m/s feedback:\ The raindrop reaches a constant terminal velocity when the downward \ force of gravity is balanced by the upward force of air resistance. \ The graph shows that this occurs when the raindrop's velocity is 4.0 \ m/s. [question20] type:2 caption:\ If a falling stone has an acceleration of 10 m/s2 what is \ its speed when it has been falling from rest in a straight line for \ 4.0 seconds? correct:40 m/s wrong1:20 m/s wrong2:4.0 m/s wrong3:2.5 m/s feedback:\ acceleration = velocity change/time\ so,\ velocity change = acceleration x time = 10 x 4.0 = 40 m/s.\ Since the stone is falling is a straight line from rest its speed \ change will equal its velocity change = 40 m/s.